Who Can Answer These Problems?
|
Ads By CbproAds |
plz answer the best u can for 10 points =]
—A home is built to be built on a 56 ft 9 in wide lot. The house is 5 ft 5 in from the side of the lot and s 34 ft 10 in wide. HOW FAR IS THE HOUSE FROM THE OTHER SIDE OF THE LOT?
—A forrest ranger can see for a distance of 12 miles from a firetower. HOW MANY SQUARE MILES CAN E OBSERVE?
—-9 3/4 acres of land of acres are divided into lots of at least 2/3 acres each.WHAT IS THE MAXIMUM NUMBER OF LLOTS THAT CAN BE CREATED?
—An electronic firm finds that 4% of its resistors are defective. HOW MANY RESISTORS DO THEY HAVE TO MAKE TO DELIVER 5,000 RESISTORS?
—An artist agrees to paint a landscape painting at $0.30 per square inch. IF THE PAINTING IS 13 INCHES BY 17 INCHES, HOW MUCH SHOULD THE ARTIST CHARGE?
—how much wire will frank need to fence a rectangular garden that is 300 feet by 250 feet.
Related posts:
- Can Anyone Help Me With These Calculus Problems? I have not understood most of this entire chapter we...
- How Much Does It Cost For Landscaping Back Yard With French Drains, Couple Of Cement Pads, Sitting Wall ? I am moving to new house and there is a...
- How Much Does It Cost For Landscaping Back Yard With French Drains, Couple Of Cement Pads, Sitting Wall ? I am moving to new house and there is a...
- I Need More Info About Claude Monet And I Want To Know If These Are Good Information About The Painter? Claude Monet was born on November 14 1840. His Father...
- How Many Bags Of Rubber Mulch Do I Need For My Landscaping Project? ok for example……Originally I calculated square feet. when i put...
- Optimization Problem?!!?? What’s The Best Way To Do This Problem.?
- Applied Optimization For Calculus?
- How Much Does It Cost For Landscaping Back Yard With French Drains, Couple Of Cement Pads, Sitting Wall ?
- How Much Does It Cost For Landscaping Back Yard With French Drains, Couple Of Cement Pads, Sitting Wall ?
- Applied Optimization In Calc….pls Help…im Stuck!?
i’ll just give you the formulas, this way you can do your own homework
1). 56′ 9″ – 5′ 5″ – 34′ 10″ = distance to other side
2). area = pi*r^2
square miles = 3.14*6^2
3). 9 3/4 = 9 9/12
2/3 = 8/12
(9 9/12) / (8/12) = max number of lots
4). x – (x*0.04) = 5000 solve for x
5). 13*17 = # square inches of painting (x)
x*0.3 = amount artist should charge in cents
6). perimeter (P) = 2*(L+w)
P = 2*(300+250)
P = amount of wire
1.since 1 inch = 1/12 of a foot
56 ft 9 in = 56 9/12
5ft 5in = 5 5/12
34ft 10in= 34 10/12
5 5/12 + 34 10/12 =
65/12 + 418/12 = 483/12